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x^2-289x+5184=0
a = 1; b = -289; c = +5184;
Δ = b2-4ac
Δ = -2892-4·1·5184
Δ = 62785
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-289)-\sqrt{62785}}{2*1}=\frac{289-\sqrt{62785}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-289)+\sqrt{62785}}{2*1}=\frac{289+\sqrt{62785}}{2} $
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